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Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. The mean number of hours was 2.8 with a standard deviation of 2.6. A sociologist claims that people watch a mean of 3 hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day is less the claim? Use the a=0.5 level of significance and the P-value method with the TI-84 Plus calculator.

(a) State the appropriate null and alternate hypotheses.

H0: Mu = 3
H1: Mu < 3

This hypothesis test is a _____ test.

(b) Compute the P-value. Round the answer to at least four decimal places

P-value =

User DJ Forth
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1 Answer

5 votes

Answer:

a) Null hypothesis:
\mu \geq 3

Alternative hypothesis:
\mu < 3

This hypothesis test is a left tailed test.

b)
t=(2.8-3)/((2.6)/(√(1310)))=-2.784

The p value for this case can be calculated with this probability:


p_v =P(z<-2.784)=0.0027

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value
\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select
< \mu_o. Then press Calculate.

And we got the same results.

Explanation:

Information given


\bar X=2.8 represent the sample mean


s=2.6 represent the population standard deviation


n=1310 sample size


\mu_o =3 represent the value to test


\alpha=0.5 represent the significance level for the hypothesis test.

t would represent the statistic


p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:

Null hypothesis:
\mu \geq 3

Alternative hypothesis:
\mu < 3

This hypothesis test is a left tailed test.

Part b

The statistic is given by:


t=(\bar X-\mu_o)/((s)/(√(n))) (1)

Replacing the info given we got:


t=(2.8-3)/((2.6)/(√(1310)))=-2.784

The p value for this case can be calculated with this probability:


p_v =P(z<-2.784)=0.0027

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value
\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select
< \mu_o. Then press Calculate.

And we got the same results.

User Tushar Patel
by
3.7k points