Answer:
Hypotenuse = 5√2 units
Explanation:
Triangle ABC:
The legs are 5 units each
Opposite = 5unit
Adjacent = 5unit
Triangle ACB:
lengths of sides A C and C B are 5
The legs are 5 units each
Leg =AC = Opposite = 5unit
Leg = CB = Adjacent = 5unit
The hypotenuse for both ∆ACB is unknown. Since ∆ACB is a right angled triangle, we would apply Pythagoras theorem to find the hypotenuse.
Using Pythagoras theorem:
Hypotenuse ² = opposite ² + adjacent ²
Hypotenuse ² = leg² + leg²
AB = hypotenuse in ∆ACB
AB² = 5² + 5²
AB² = 25+25 = 50
AB = √50 = √(25×2)
AB = 5√2
Hypotenuse = 5√2 units