Question

A gas has a volume of 1140 ml at 37 ºC and 82.6 kPa pressure. Calculate its volume at STP.

Answer 1

The volume of a gas at standard temperature and pressure (STP) can be calculated using the molar volume of gases which is 22.4 L/mol.

Step-by-step explanation:

The volume of a gas at standard temperature and pressure (STP) can be calculated using the molar volume of gases which is 22.4 L/mol. At STP, any gas has a volume of 22.4 L per mole of gas. In this case, if the gas has a volume of 1140 ml at 37 ºC and 82.6 kPa pressure, we can convert the volume to liters by dividing it by 1000 (since 1 L = 1000 ml). The volume at STP would be:

(1140 ml / 1000) * (273 K / 37 ºC) * (82.6 kPa / 1 atm) * (22.4 L / 1 mol) = X L

Where X is the volume at STP in liters.

Answer 2

Volume, V2 at STP = 818.61ml.

Step-by-step explanation:

Given the following parameters;

Volume, V1 = 1140ml

Volume, V2 =?

Temperature, T1 = 37ºC to Kelvin = 273+37 = 310K

Temperature, T2 = 273K is the standard temperature.

Pressure, P1 = 82.6kPa

Pressure, P2 = 101.3kPa is the standard pressure.

To solve for volume at standard temperature and pressure (STP), we would use the combined gas law;

The combined gas law is a combination of the other three gas laws, namely Gay Lusac's law, Boyle's law and Charles's law.

Combined gas law states that the ratio of the product or multiplication of volume and pressure to the temperature of a gas is equal to a constant.

Mathematically,
`PV/T = K`

P1V1/T1 = P2V2/T2

Let's make V2 to the subject formula;

Cross multiplying gives,

P1V1T2 = P2V2T1

Hence,
`V2 = (P1V1T2)/P2T1`

Substituting the parameters;

V2 = (82.6*1140*273)/101.3*310

V2 = 25706772/31403

V2 = 818.61ml.