Question

If the angles are represented in degrees, find both angles: \cos(3x+13)=\sin(2x+42) cos(3x+13)=sin(2x+42)

Answer 1

cos34°

sin56°

Explanation:

Sin(2x+42)= sin90-(3x+13)

Sin(2x+42) = sin(90-13-3x)

Sin(2x+42) = sin(77-3x)

2x + 42 = 77-3x

5x. = 35

X = 7

If x = 7

cos(3x+13) = cos((3*7)+13)

cos(3x+13) = cos(21+13)

cos(3x+13)= cos34

And

sin(2x+42) = sin((2*7)+42)

sin(2x+42)= sin (14+42)

sin(2x+42) = sin56