Question

Suppose ø is an angle in the standard position whose terminal side is in Quadrant I and tan ø = 60/11

Answer 1

Following are the ratio to this question:

Explanation:

Given:

`\bold{\tan \phi = (60)/(11) }\\\\`

Formula:

`\sin \phi = (Perpendicular)/(Hypotenuse)\\\\\cos \phi = (Base)/(Hypotenuse) \\\\\tan \phi = (Perpendicular)/(Base) \\\\\ cosec \phi = (Hypotenuse)/(Perpendicular)\\\\\sec \phi =(Hypotenuse)/(Base)\\\\\cot \phi = (Base)/(Perpendicular)\\\\`

`\ Base = 11 \\\ Perpendicular =60\\\ Hypotenuse= 61\\`

`\sin \phi = (60)/(61)\\\\\cos \phi = (11)/(61) \\\\\tan \phi = (60)/(11) \\\\\ cosec \phi = ( 61)/(60)\\\\\sec \phi =(61)/(11)\\\\\cot \phi = (11)/(60)\\\\`