102k views
2 votes
The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

(x - 4)² + y² = 2√3
(x - 4)² + y² = 12
(x + 4)² + y² = 12

2 Answers

0 votes

Answer:

B?

Explanation:

User Dimentica
by
7.4k points
4 votes

Answer:

B. (x - 4)² + y² = 12

Explanation:

Rewrite in standard form to find the center (h,k) and radius r.

User Artem Zelinskiy
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.