The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is (x - 4)² + y² = 2√3 (x - 4)² + y² = 12 (x + 4)² + y² = 12

asked Nov 23, 2021 102k views

2 votes

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

(x - 4)² + y² = 2√3
(x - 4)² + y² = 12
(x + 4)² + y² = 12

4.6k points

Please log in or register to add a comment.

0 votes

Answer:

Explanation:

Dimentica answered Nov 24, 2021

5.1k points

4 votes

Answer:

B. (x - 4)² + y² = 12

Explanation:

Rewrite in standard form to find the center (h,k) and radius r.

4.0k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.4m questions

5.6m answers