The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is (x - 4)² + y² = 2√3 (x - 4)² + y² = 12 (x + 4)² + y² = 12

asked Nov 23, 2021 102k views

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The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

(x - 4)² + y² = 2√3
(x - 4)² + y² = 12
(x + 4)² + y² = 12

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Answer:

Explanation:

Dimentica answered Nov 24, 2021

5.7k points

4 votes

Answer:

B. (x - 4)² + y² = 12

Explanation:

Rewrite in standard form to find the center (h,k) and radius r.

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