Answer:
a) p=0.021
b) p=0.029
c) Exactly one audit: P=0.0965
More than one audit: P=0.0042
Explanation:
a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:
![p_1=(21)/(1,000)=0.021](https://img.qammunity.org/2021/formulas/mathematics/college/si8rbu9qhg0heoc0wdf7lbkx5lobcez0jc.png)
If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:
![p_2=(29)/(1,000)=0.029](https://img.qammunity.org/2021/formulas/mathematics/college/tsyehfuyjl7jq2n87lermlsazkccgs2jyv.png)
b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:
![P(x=1) = \dbinom{5}{1} p^(1)q^(4)=5*0.021*0.9186=0.0965\\\\](https://img.qammunity.org/2021/formulas/mathematics/college/dcend702evtgxq9y8bwdh0r7j35aeelqjf.png)
There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.
To calculate the probability that more than one will be audited, we use the same distribution:
![P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^(0)q^(5)=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^(1)q^(4)=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042](https://img.qammunity.org/2021/formulas/mathematics/college/vq6br5xz0lod3jp5olukkp01qhty7oar4d.png)
There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.