Answer:
4:42 a.m.
Explanation:
The earliest low tide occurs by 2:00 a.m. and the earliest high tide occurs by 8:00 a.m.
Between these hours, 6 hours elapsed.
The lowest point is 1.1 m and increases steadily to 5.3 m.
Let us take 2:00 a.m. as the zeroth hour, and 8:00 a.m. as the 6th hour, we can safely interpolate as below,
0 = 1.1 m
x = 3 m
6 = 5.3 m
we solve as
=
![(3 - 1.1)/(5.3 - 1.1)](https://img.qammunity.org/2021/formulas/mathematics/college/10yp78ok8sskvrvtyo3h2dkly0cqx1jta2.png)
=
![(1.9)/(4.2)](https://img.qammunity.org/2021/formulas/mathematics/college/v5fyci4itbkf6z87vyfl8cz3eo9ya3lj6w.png)
4.2x = 11.4
x = 2.71 hours from 2:00 a.m.
= 2 hrs + (0.71 x 60)min = 2 hrs 42.6 min
the time will approximately be by 4:42 a.m.