Question

What is the molarity of 0.945 L of a solution that contains 0.227 moles of Fe(NO3)3?

Answer 1

0.2402 M

Step-by-step explanation:

0.945 L sol contains = 0.227 moles

1 L sol will contain = (0.227/0.945)*1 = 0.2402 moles

Molarity = 0.2402 moles/L or M