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Please help! I've been on this question for more than an hour...

You pick a card at random. Without putting the first card back, you pick a second card at random.

What is the probability of picking an even number and then picking an even number?

Simplify your answer and write it as a fraction or whole number.

Please help! I've been on this question for more than an hour... You pick a card at-example-1
User Iman Rb
by
8.1k points

2 Answers

5 votes

Answer:

1/6

Explanation:

Out of these four card choices, for the first pick there are two even cards and four cards in total. This means that on the first pick there is a 2/4=1/2 chance that you pick an even card. On the second pick, if you do not replace the card, then there is 1 even card remaining, and 3 cards in total, leaving a probability of 1/3. Multiplying these two probabilities together, you get an overall chance of 1/6. Hope this helps!

User Toshiyuki
by
7.9k points
5 votes

1/6 and you got the comment why

User Kodi
by
8.5k points

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