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Question 2 In the reaction: P4+6C12 - 4PC13 How many grams of P4 are required for the complete reaction of 2.40 moles of CIZ? 0 0.1168 12.4g 298 g 1988 49.6 g
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Question 2

In the reaction:
P4+6C12 - 4PC13
How many grams of P4 are required for the complete reaction of 2.40 moles of CIZ?
0 0.1168
12.4g
298 g
1988
49.6 g

User Viatcheslav Ehrmann
by
8.3k points

1 Answer

4 votes
I think the answer should be 12.4g but idk why u don’t have abcd
User EvgeniyZh
by
8.3k points
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