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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets? A 13 B. 40 56 D. 64 Reset
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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the

tickets?
A
13
B. 40
56
D.
64
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User Keeely
by
5.4k points

1 Answer

3 votes

Answer:

D. 56

Explanation:

8!/3!x5!= 56

User Marius Tanasoiu
by
6.5k points
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