Question

Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.

-7 C
11 C
15.5 C
288 C

Answer 1

Answer:
`15.5^0C`

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =
`0.0821Latm/Kmol`

T =temperature = ?

`T=(PV)/(nR)`

`T=(0.987atm* 12L)/(0.0820 L atm/K mol* 0.50mol)=288.5K=(288.5-273)^0C=15.5^0C`

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is
`15.5^0C`