Question

The sum of two numbers is 41. The larger number is one less than twice the smaller number. Find the numbers.

plz help

Answer 1

14 and 17

Explanation:

x+y=41

y=2x-1

x+(2x-1)=41

3x-1=41

3x=42

x=14

y=2(14)-1=27

Answer 2

Explanation:

Step 1: Make a system of equation

The sum of two numbers is 41

x + y = 41

The larger number is one less than twice the smaller number.

x = 2y - 1

Step 2: Substitute x from the second equation into the first

`x + y = 41`

`(2y - 1) + y = 41`

`3y - 1+ 1 = 41 + 1`

`3y/3 = 42 / 3`

`y = 14`

Step 3: Substitute y into the second equation

`x = 2y - 1`

`x = 2(14) - 1`

`x = 28 - 1`

`x = 27`

Answer:
`x = 27, y = 14`