Question

Which equation is the inverse of (x-4)2- ß-by-122

O y=6x2-3x+42
6x-
34
O y=4+ /6x-
34
O y=-4+ /6x-
0 -(x-4)2 -> --6y+12

Answer 1

see below

Explanation:

Interchange x and y, then solve for y.

`(x-4)^2-(2)/(3)=6y-12\qquad\text{given}\\\\(y-4)^2=6x-(36-2)/(3)\qquad\text{swap x,y; add 2/3}\\\\y-4=\pm\sqrt{6x-(34)/(3)}\\\\\boxed{y=4\pm\sqrt{6x-(34)/(3)}}`