Question

URGENT HELP NEEDED! PLEASE ANSWER WITH EXPLANATION*

Much appreciated

1) An 85.0 g sample of copper is initially at 22.2 ∘C What is the final temperature if the sample absorbs 2.35 kJ of heat?

The specific heat of Cu is 0.385 J/(g^ Degree C)

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2) A 75.0 g sample of aluminum is heated to 65.3 ∘C then allowed to cool. What is the final temperature if the sample releases 2.07 kJ of heat?

The specific heat of Al is 0.903 J/(g degree C)

Answer 1

1) 94.0° C, 2) 34.7°C

Step-by-step explanation:

1)

Q=mcΔt° =mc(t2 - t1)

2350 J = 85.0 g* 0.385 J/(g*°C) *(t2 - 22.2°C)

t2 - 22.2°C = 71.81°C

t2 = 94.0° C

2)

Q=mcΔt° =mc(t2 - t1)

- 2070 J = 75.0 g * 0.903 J/(g*°C) *(t2 -65.3°C)

t2 - 65.3°C = - 30.56°C

t2 = 34.7°C