Question

Determine the solution that exists to the equation below.
8(j-4)=2(4j-16)

Answer 1

All Real Numbers Are Solutions

Step-by-step explanation:

8(j − 4) = 2(4j − 16)

[ Simplify both sides of the equation ]

8(j − 4) = 2(4j − 16)

(8)(j) + (8)(−4) = (2)(4j) + (2)(−16) (Distribute)

8j + −32 = 8j + −32

8j − 32 = 8j − 32

[ Subtract 8j from both sides ]

8j − 32 − 8j = 8j − 32 − 8j

−32 = −32

[ Add 32 to both sides ]

−32 + 32 = −32 + 32

0 = 0

Therefore, all real numbers are solutions.

Answer 2

infinite solutions

Step-by-step explanation:

8(j-4)=2(4j-16)

Distribute

8j - 32 = 8j - 32

Subtract 8j from each side

8j-8j -32 = 8j-8j -32

-32 = -32

This is always true so there are infinite solutions