Question

What is the distance between the points 3, 7 and 15, 6 on a coordinate plane

Answer 1

distance = Sqrt((x2-x1)^2 +(y2-y1)^2)

Explanation:

Answer 2

`D=√(145 )\\`

Explanation:

We are actually using Pythagorean theorem here but to be simple

we can use the equation:

D(distance)=
`\sqrt{(x_(1)- x_(2) )^(2) +( y_(1)-y_(2))^(2)}`

=

`D=\sqrt{(15-3)^(2)+(6-7)^(2) } =\\D=\sqrt{(12)^(2)+(-1)^(2) } =\\\\D=√(144+1 ) =\\D=√(145 )\\`

(If you meant 16 instead of 6 the answer would be 15)

Hope this helps!