Answer:
Slant height of the pyramid = 11.66 m
Explanation:
A squad pyramid has a volume of
V = ⅓ × (area of base) × (vertical height)
Area of the pyramid's square base = 144 m²
Volume = 384 m³
384 = ⅓ × 144 × (vertical height)
Vertical height = (3×384)/(144) = 8 m
But, the slant height of the square based pyramid forms a right angled triangle with the vertical height of the pyramid and the distance from the centre of the base of the pyramid to an edge of the pyramid.
The distance from the centre of the base of the pyramid to an edge of the pyramid = half of the length of the diagonal of the square base of the pyramid.
The diagonal of the square base of the pyramid also forms a right angled triangle with two sides of the square base of the pyramid.
Area of the square base of the pyramid = 144 m²
Area of a square = (side length)²
Side length = √(Area of the square) = √144 = 12 m
Using Pythagoras theorem,
(Length of the diagonal)² = 12² + 12² = 288
Length of the diagonal = (12√2) m
Half of the length of the diagonal of the square base = 6√2 m
Using Pythagoras theorem further
(Slant height of the pyramid)² = (vertical height of the pyramid)² + (Half of the length of the diagonal of the square base)²
(Slant height of the pyramid)² = 8² + (6√2)² = 64 + 72 = 136
Slant height of the pyramid = √136 = 11.66 m
Hope this Helps!!!