Question

Help solving this problem

Answer 1

A=0.50

B=0.477

C=0.423<p<0.531

Explanation:

sample size N :333

number of success X: 159

sample part of success x/n = 159/333

x=0.477 B

0.50 A Half a chance to flip a tail or head

part C:

`0.477 plusminus 1.96 * \sqrt{ (0.477 (1 - 0.477))/(333) }`

simplify

`0.477 plusminus 1.96 * 0.0536`

expand

`0.477 + 1.96 * 0.0536`

`0.531`

expand minus

`0.477 - 1.96 * 0.0536`

`0.423`

finally answer part c

`0.423 < p < 0.531`