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(2x+3)(4x-1)<8x^(2)+1

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1 Answer

5 votes

Answer:
x<(2)/(5)

Explanation:


(2x+3)(4x-1)<8x^2+1

Begin by multiplying parentheses.


(2x*4x)+(2x*-1)+(3*4x)+(3*-1)<8x^2+1


(8x^2)+(-2x)+(12x)+(-3)<8x^2+1


8x^2-2x+12x-3<8x^2+1

Subtract
8x^2


8x^2-2x+12x-3+(-8x^2)<8x^2+1+ (-8x^2)


-2x+12x-3<1

Add 3


-2x+12x-3+3<1+3


-2x+12x<4

Combine like terms;


10x<4

Divide by 10


x<(4)/(10)

Simplify;


x<(2)/(5)

User By Richard Powell
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