Answer:
![Q=1.16kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/yesirkqqlqi2m5mzrzwbvherxv1jw34twv.png)
Step-by-step explanation:
Hello,
in this case, the required heat to increase the water by 5.53 °C is computed by using the mass, heat capacity and change in temperature during the process:
![Q=mCp\Delta T](https://img.qammunity.org/2021/formulas/chemistry/high-school/duo84kyyvcf1p96l6zkuz0a9tkhqsxk9ay.png)
Thus, for the given data we compute it in kJ:
![Q=50g*4.186(J)/(g*\°C)*(5.53\°C)*(1kJ)/(1000J) \\\\Q=1.16kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/59nrssxxxh37zyd1cey5torhms3jjag470.png)
Best regards.