Question

What is the equation of the line that has a slope of -4 and passes through the point (2, 3)?

Answer 1

y = -4x + 11

Explanation:

Slope m= -4

Point (2,3)

`y- y_(1)=m(x-x{1})\\`

y - 3 = -4(x - 2)

y - 3 = -4x - 2 * -4

y - 3 = -4x + 8 {add 3 to both sides}

y -3 + 3 = -4x + 8 + 3

y = -4x + 11