Question

Let f(x)=3x^2-8 and let g(x)=4x+1. Find the given value f[g(-1)]

Answer 1

19

Explanation:

given:

f(x)=3x²-8

g(x)=4x+1

g(-1) = 4(-1)+1

g(-1) = -4 + 1

g(-1) = -3

hence

f[g(-1)]

= f(-3)

= 3(-3)²-8

= 3(9) - 8

= 19