Answer:
1/12
Explanation:
Let the sample space be S.
Let the event of obtaining an even number on one dice and 1 on the other dice be E.
The sample space (S) of rolling a two fair six-sided dice is shown below:
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,1 6,3 6,4 6,5 6,6
n(S) = 36
The event (E) of obtaining an even number on one dice and 1 on the other dice is given below:
2,1 4,1 6,1
Therefore, n(E) = 3
The probability of obtaining an even number on one dice and 1 on the other dice is given below:
P(E) = n(E) / n(S)
P(E) = 3/36
P(E)= 1/12
Therefore, the probability of obtaining an even number on one dice and 1 on the other dice is 1/12