Question

THIS IS DUE TODAY!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

`\large \boxed{\text{0.1767 mol/L}}$`

Step-by-step explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O

(b) Moles of NaOH

`\text{Moles of NaOH} = \text{34.52 mL NaOH} * \frac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}`

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

`\text{Moles of H$_(3)$PO}_(4) = \text{13.26 mmol NaOH} *\frac{\text{ 1 mmol H$_(3)$PO}_(4)}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H$_(3)$PO}_(4)`

(d) Molar concentration of H₃PO₄

`c = \frac{\text{moles of solute}}{\text{litres of solution}}\\\\c = (n)/(V) = \frac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol $\cdot$ L$^(-1)$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{0.1767 mol/L}}$}`