Question

I’m willing to give lots of points for this question ;)

Answer 1

`Cu^(2+) + 2e^(-) --> Cu^(0) ||reduction||cathode`

`2O^(-2) -4e^(-)-->O_(2)^(0)|| oxidation|| anode`

`Li^(+) +1e^(-)--> Li^(0) || reduction|| cathode`

`2H^(+) + 2e^(-)-->H_(2)^(0)|| reduction||cathode`

`Mg^(2+) +2e^(-) --> Mg^(0)|| reduction|| catode`

`Al^(3+)+3e^(-) --> Al^(0)||reduction||cathode`

Metal ions have positive charges, and are attracted to the negative electrode (the cathode) and are reduced during electrolysis.

Non-metal ions have negative charges, and are attracted to the positive electrode (the anode) and are oxidized during electrolysis.