Question

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 Green crayons. A crayon is selected, NOT replaced, then another is selected. Find the probability of two reds.

P(two reds)

Answer 1

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 Green crayons.

=> Number of red crayons: 8

=> Total number of crayons: N = 8 + 14 + 6 + 4 = 32

=> The probability of selecting 2 red ones sequentially (without replacement):

P = (8/32) x (7/31) = 0.06

Hope this helps!

:)

Answer 2

Explanation:

8+14+6+4=32

`(8)/(32)`

1

_

4