Question

Determine the function’s value when x = −1.

g(x) = x3 + 6x2 + 12x + 8

Answer 1

g(-1) = 1

Explanation:

Using " ^ " to denote exponentiation, we get:

g(x) = x^3 + 6x^2 + 12x + 8

Substituting -1 for x, we get:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8, or

g(-1) = -1 + 6 - 12 + 8, or

g(-1) = 1