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1 vote
(x – 3)^2 + (y + 6)^2 = 16

the radius of the circle is ?

User Wsl
by
5.7k points

2 Answers

6 votes

Answer:

4

Explanation:

By comparing with the canonical form of the equation of a circle

(X-Xo)^2 + (Y-Yo) ^2 = r^2; Xo and Yo are the coordinates of the centre of the circle

r^2= 16 >> r = 4

User Yestay Muratov
by
5.7k points
3 votes

Answer:

The center is (3, -6) and the radius is 4

Explanation:

(x – 3)^2 + (y + 6)^2 = 16

We can write the equation of a circle as

(x – h)^2 + (y -k)^2 = r^2

Where (h,k) is the center and r is the radius

(x – 3)^2 + (y - -6)^2 = 4^2

The center is (3, -6) and the radius is 4

User StanK
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6.1k points