Question

Show how you would prepare a 0.1 M solution of potassium hydroxide with .0025 moles of potassium hydroxide.

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Answer 1

0.025 L KOH

Step-by-step explanation:

Because you gave molarity and moles, I am assuming that you are looking for volume via the molarity equation. I simply plugged the given values into the molarity equation and rearranged to isolate the liters variable.

Molarity (M): 0.1 M

Moles: 0.0025 moles

Volume (L): ? L

Molarity (M) = moles / liters (L)

0.1 M KOH = (0.0025 moles KOH) / (? L KOH)

(0.1 M KOH) x (? L KOH) = 0.0025 moles KOH

? L KOH = (0.0025 moles KOH) / (0.1 M KOH)

? L KOH = 0.025 L KOH