Question

Write the equation of a circle whose center is at (3,-2) and has a radius of 11.

Show your work!

Answer 1

`(x - 3)^(2) + (y + 2)^(2) = 121`

Explanation:

The equation of a circle has the following format:

`(x - x_(0))^(2) + (y - y_(0))^(2) = r^(2)`

In which r is the radius and the centre is the point
`(x_(0), y_(0))`

In this question:

Center at (3,-2), so
`x_(0) = 3, y_(0) = -2`

Radius 11, so
`r = 11`

Then

`(x - 3)^(2) + (y - (-2))^(2) = 11^(2)`

`(x - 3)^(2) + (y + 2)^(2) = 121`