Question

Factor the tribunal into two binomials than solve?

Answer 1

`(x-5)(x-3)=0`

`x=5 \text{ and } x=3`

Explanation:

Quadratic Equation given:

`x^2-8x+15=0`

In order to factor this equation think that we'll have something in the format:
`(x-a)(x-b)`

Once: -a -b = -c

and (-a)(-b)= d

Therefore, we have

`(x-5)(x-3)=0`

`x-5=0\\\text{or}\\x-3=0`

`x=5 \text{ and } x=3`