Question

b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and the standard error for such means is 1.42

Answer 1

99% of confidence intervals for mean age of ICU patients

(53.8920 , 61.2079)

Explanation:

Explanation:-

Given sample mean
`x^(-) = 57.55`

Given standard error is determined by

S.E =
`(S.D)/(√(n) )`

Given data standard error = 1.42

99% of confidence intervals for mean is determined by

`(x^(-) - Z_(0.01) (S.D)/(√(n) ) , x^(-) + Z_(0.01) (S.D)/(√(n) ) )`

`Z_{(\alpha )/(2) } = Z_{(0.01)/(2) } = Z_(0.05) = 2.576`

`(x^(-) - 2.576 S.E , x^(-) + 2.576 S.E)`

`(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)`

(53.8920 , 61.2079)

Conclusion:-

99% of confidence intervals for mean is determined by

(53.8920 , 61.2079)