Question

A rocket is launched from the top of a 100-foot cliff with an initial velocity of 34 feet per second. The height of the rocket t seconds after launch is given by the equation h=−16t2+34t+100. How high will the rocket be after 1 second?

Answer 1

118 feet

Explanation:

h= -16t² + 34t +100

In order to find the height of the rocket after 1 second, we substitute t=1 in the above equation

h= -16(1)² + 34(1) +100

h=-16 + 34 +100

h=118 feet

Thus, the rocket will be 118 feet high after 1 second