Question

Q goes through points (-3,3) and (-5,-3). At what point does line q cross the y-axis.

Answer 1

Explanation:

Given that;

`x_1= -3,\\ y_1 = 3, x_2= -5,\\ y_2 = -3`

slope of the line is

`m = (y_2 -y_1)/(x_2 -x_1)`

`m =(-3 -3)/(-5 +3)\\\\=(-6)/(-2) \\\\= 3`

To find the intercept we use the formula:

y = mx +b

y = 3

m = 3

x = -3

we can solve for b

`3 = 3*(-3) +b\\3=-9+b b = 3 +9 =12`

Therefore, the point where the line q cross the y-axis is (0,12)

Answer 2

`m = (y_2 -y_1)/(x_2 -x_1)`

And replacing we got:

`m =(-3 -3)/(-5 +3)= 3`

Now we can find the intercept using the following general formula:

`y = mx +b`

And using one of the points we can solve for b and we got:

`3 = 3*(-3) +b`

`b = 3 +9 =12`

And for this case the line cross the y axis since represent the y intercept.

So then the point where the line q cross the y-axis is (0,12)

Explanation:

We have two points given :

`(x_1= -3, y_1 = 3)`

`(x_2= -5, y_2 = -3)`

We can find the slope of the line like this:

`m = (y_2 -y_1)/(x_2 -x_1)`

And replacing we got:

`m =(-3 -3)/(-5 +3)= 3`

Now we can find the intercept using the following general formula:

`y = mx +b`

And using one of the points we can solve for b and we got:

`3 = 3*(-3) +b`

`b = 3 +9 =12`

And for this case the line cross the y axis since represent the y intercept.

So then the point where the line q cross the y-axis is (0,12)