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Graph the circle x2 + y2 + 10x + 6y + 18 = 0.

2 Answers

6 votes

Answer:

The graph is formed from the equation

(X+5)^2. + (Y+3)^2. = 16

Explanation:

Shown by the attachment

Graph the circle x2 + y2 + 10x + 6y + 18 = 0.-example-1
User Mike Ounsworth
by
8.8k points
4 votes

Answer:

see below for a graph

Explanation:

Completing the square for x and y terms can help you put this in the standard form.

(x^2 +10x) +(y^2 +6y) = -18

(x^2 +10x +25) +(y^2 +6x +9) = -18 +25 +9 . . . . add square of half linear coefficient

(x +5)^2 +(y +3)^2 = 16 . . . . . . . circle centered at (-5, -3) with radius 4

Graph the circle x2 + y2 + 10x + 6y + 18 = 0.-example-1
User Jim Mack
by
7.5k points

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