Answer:
StartFraction StartRoot 30 EndRoot minus 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot minus StartRoot 33 EndRoot Over 2
Explanation:
Given the surdic equation as shown
![(√(6)+√(11) )/(√(5)+√(3) )\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bowey4690ufodjdcuebsxpzyox31cm0o8o.png)
To find the quotient, we will rationalize by multipying both numerator and denominator of the function by the conjugate of the denominator.
Given the denominator
, its conjugate will be
![√(5)-√(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lsw7nvt7p036oxbsf49fk40edyi51sgis6.png)
Multiplying through by
, we have;
![= (√(6)+√(11) )/(√(5)+√(3) ) * (√(5)-√(3) )/(√(5)-√(3) )\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rwuw8y31zr17a6mx98pvhlnah5qwx0rfzh.png)
![= (√(30)- √(18)+√(55)-√(33))/(2)\\= (√(30)- √(9*2)+√(55)-√(33))/(2)\\= (√(30)- 3√(2)+√(55)-√(33))/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5iopsmnze3oh6gwhl590g958quul1tpz3o.png)
The final expression gives the requires answer