Question

Admita uma solução aquosa saturada de HCL com concentração percentual mássica de 36,5% e densidade igual a 1g/mL. Calcule a concentração molar dessa solução, expressa em mol/L

Answer 1

Molar concentration of the solution = 10.0 mol/L

Step-by-step explanation:

English Translation

Admit a saturated aqueous solution of HCL with a mass percentage concentration of 36.5% and density equal to 1g / mL. Calculate the molar concentration of this solution, expressed in mol / L

Solution

Mass concentration of the solution = 1 g/no

Percentage concentration of the solution that is HCl = 36.5%

Mass concentration of HCl

= 36.5% × 1g/mL = 0.365 g/mL

(Concentration in mol/L) = (Concentration in g/L) ÷ (Molar Mass)

Concentration of HCl in g/L = 365 g/L

Molar Mass of HCl = 36.46 g/mol

Concentration of HCl in mol/L = 365 ÷ 36.46 = 10.011 mol/L = 10.0 mol/L

Hope this Helps!!!

Answer 2

Molar Concentration of the solution = 10 mol / L

Step-by-step explanation:

Given that :

Data: H = 1 u; Cl = 35.5 u

the mass percentage concentration is 36.5% → 36.5 g in 100 g of solution

density = 1 g / mL

Molar mass of (HCl) = 1 g + 35.5 g = 36.5 g / mol

Molar Concentration =unknown??? (mol / L)

We all know that:

density = mass / Volume

1 g / mL = 100 g / V

V = 100 mL → 0.1 L

Also

number of moles = mass / molar mass

n = 36.5 g / 36.5 g / mol

n = 1 mol

Molar Concentration = number of moles / Volume

Molar Concentration = 1 mol / 0.1 L

Molar Concentration of the solution = 10 mol / L