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The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. Find m+b. Note: The perpendicular bisector of the line segment AB is the line
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The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. Find m+b. Note: The perpendicular bisector of the line segment AB is the line that passes through the midpoint of AB and is perpendicular to AB.

User PoloDelaVega
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Answer:

16

The formula of the line is y=2x+14 and 2 is m and 14 is b so m+b=16

User Johnny Svarog
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