Question

A gas absorbs 21.39 kJ of energy while expanding against 0.276 atm from a volume of 0.0432 L to 1.876 L. What is the energy change of the gas?

Answer 1

`\Delta E=21.34kJ`

Step-by-step explanation:

Hello,

In this case, we should apply the first law of thermodynamics to compute the energy change:

`\Delta E=Q-W`

Thus, with the given volume change we compute the corresponding work in kJ:

`W=P\Delta V=0.276atm*(1.876L-0.0432L)*(101.325kPa)/(1atm)*(1m^3)/(1000L)=0.0513kJ`

Then, we compute the energy change:

`\Delta E=21.39kJ-0.0512kJ\\\\\Delta E=21.34kJ`

Best regards.

Answer 2

Q = 21.896kJ

Step-by-step explanation:

Q = ?

∇U = 21.39kJ

W = ?

W = P∇V

W = P (V2 - V1)

W = 0.276 × (1.876 - 0.04232)

W = 0.276 × 1.83368

W = 0.5060J

Q = ∇U + W

Q = 21.39 + 0.5060

Q = 21.896kJ

The energy change corresponds to the work done by the system