Question

How many joules of heat are given off when 10 g of water cool from 100 C to 25 C?

Answer 1

3138 joules

Step-by-step explanation:

Heat flow equation => q = m·c·ΔT

m = mass of substance = 10 grams

c = specific heat = 4.184 j/g·°C

ΔT = 100°C - 25°C = 75°C

q = m·c·ΔT = (10g)(4.184 j/g·°C)(75°C) = 3138 joules