Answer:
Equilibrium constant is equal to
![29.162](https://img.qammunity.org/2021/formulas/chemistry/high-school/kpv92hzz4c91ep2xruwfnomfsliz556phr.png)
Step-by-step explanation:
If the reaction is of this form
aA(g) + bB(g) ⇄ cC(g) + dD(g)
Then , the Kp of this equation will be equal to
![K_p =(P_C^cP_D^d)/(P_B^bP_A^a)](https://img.qammunity.org/2021/formulas/chemistry/high-school/s1em8hryntuxwg5oishybjn2ylt2ijnewj.png)
Given
![P_c =](https://img.qammunity.org/2021/formulas/chemistry/high-school/h1gld8qvuprw7r45139bw6no7v76p5k0av.png)
MPa and c is equal to two
MPa
MPa
Here a and b is equal to zero.
Substituting the given values we get -
![K_p = (66.6^2)/(13*11.7)\\K_p = 29.162](https://img.qammunity.org/2021/formulas/chemistry/high-school/6wiqqyaykc2kd2dt5z2wzl6wnljh4p36f1.png)
Equilibrium constant is equal to
![29.162](https://img.qammunity.org/2021/formulas/chemistry/high-school/kpv92hzz4c91ep2xruwfnomfsliz556phr.png)