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1 vote
How many solutions does x^2-8x + 16=0 have and which ones are they

User Asheh
by
5.5k points

1 Answer

5 votes

Answer:

2

Explanation:

Given

x² - 8x + 16 = 0

Consider the factors of the constant term (+ 16) which sum to give the coefficient of the x- term (- 8)

The factors are - 4 and - 4, since

- 4 × - 4 = + 16 and - 4 - 4 = - 8, thus

(x - 4)(x - 4) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 4 = 0 ⇒ x = 4

The solution is x = 4 with multiplicity 2

User PApostol
by
5.9k points
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