Question

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select three options.

Answer 1

A: y = –Two-fifthsx – 2

B: 2x + 5y = −10

D: y + 4 = –Two-fifths(x – 5)

Explanation:

Found that most of the answers are structured differently

Answer 2

Next time, please upload your option.

The line 5x − 2y = −6 <=> 2y = 5x + 6 <=> y = (5/2)x + 3, has the slope a = 5/2

=> Another line (y = a'x + b) that is perpendicular with this line, must has slope a', that satisfies: a' x (5/2) = -1 => a' = -2/5

=> y = (-2/5)x + b

This line passes (5, -4), then we have:

-4 = (-2/5)*5 + b => -4 = -2 + b => b = -2

=> Solution is y = (-2/5)x -2

Hope this helps!

:)