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What is the center of a circle whose equation is x
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What is the center of a circle whose equation is x

What is the center of a circle whose equation is x-example-1
User Shahrzad
by
3.6k points

1 Answer

4 votes

Answer:

(6, 1)

Explanation:


{x}^(2) + {y}^(2) - 12x - 2y + 12 = 0 \\ equating \: it \: with \\ {x}^(2) + {y}^(2) + 2gx + 2fy + c= 0 \\we \: find \\ 2g = - 12 \implies \: g = - 6 \\ 2f = - 2 \implies \: f = - 1 \\ center \: of \: circle = ( - g \: \: - f) \\ center \: of \: circle = (6 \: \: 1)

User JJS
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