Question

Find the distance between the points (3,-5)
and
(3,-2).

Answer 1

3 units

Explanation:

Distance between two points (x1,y1) and (x2,y2) on coordinate plane is given by

distance =
`√((x1-x2)^2 +(y1-y2)^2 )`

Given points in the problem are (3,-5) and (3,-2).

Thus distance between points (3,-5) and (3,-2).

`distance = √((x1-x2)^2 +(y1-y2)^2 )\\=>distance = √((3-3)^2 +(-5-(-2))^2 )\\=>distance = √((0)^2 +(-5+2)^2 )\\\\=>distance = √(0 +(-3)^2 )\\\\=>distance = √(9 )\\=>distance = 3`

Distance between points (3,-5) and (3,-2) is 3 units