If you prepare 525 mL of a .650M MgCl2 solution, how many grams of solute would you need?

Question

asked Nov 19, 2021 216k views

1 Answer

Nyxm · Answer 1 · 2021-11-26T02:28:59+0000

Answer:

Step-by-step explanation:

525ml of 0.6550M MgCl₂ => 0.525L x 0.650M = 0.3413mole MgCl₂

0.3413mole MgCl₂ = 0.3413mole x 94 g/mole = 32.1g MgCl₂