Answer:
B) 3/5
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Solve
- So, we know that tantheta is 0.75, or 3 quarters, but we have to find the value of sintheta. If there are 4 angles on a triangle, we can label them as BC and AB.
![because~of~the~angles\\BC = 3k\\AB = 4k](https://img.qammunity.org/2023/formulas/mathematics/high-school/53bo1vly5fvus27tffvjmyk0iti2z54u41.png)
- Now, we must find the value of AC using the pythagoras theorem.
⇒ (AB)² + (BC)² = (AC)²
in which because of AB and BC's values, goes into...
⇒ (4k)² + (3k)² = (AC)²
because of that ↑ you get the values of what is below.
⇒ (AC)² = 16 k² + 9 k²
add 16k and 9k for the result below.
⇒ (AC)² = 25 k²
⇒ AC = ±5k
- Hmm. An angle cannot be negative, so turn 5k to positive 5k. Last but- not least, we have to find the sintheta.
the sin is the side opposite to the angle, so find the hypotenuse and opposite angle.
![Side~opposite~to~angletheta\\= BC(3k)\\\\Hypotenuse\\= AC(5k)](https://img.qammunity.org/2023/formulas/mathematics/high-school/61gd5px1mxosqsyt4l24s7lebodn4di03d.png)
That said →
![sintheta = (BC)/(AC) = (3k)/(5k) = (3)/(5)](https://img.qammunity.org/2023/formulas/mathematics/high-school/530oogu3refqle73frp241rf6ljh4khu5j.png)
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Questions?
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